Friday, June 24, 2011

Energy stored in a capacitor and inductor



Electric energy is stored in a capacitor (in an electrostatic field) and in an inductor (in an electromagnetic field).



1) Energy stored in a capacitor


We explained this in the article
"What a capacitor really is?" as below:

This can be explained without using work, which is more direct.

Capacitor function, or the relation of Capacitance, Current (changing) and Voltage (changing)

i(t)= \frac{\mathrm{d}q(t)}{\mathrm{d}t}=C\frac{\mathrm{d}v(t)}{\mathrm{d}t}

Integrate the both sides with respect to time

(q/time) x time = C v

q = Cv =C x Joule (Energy)/q

Integrate both sides with respect of q (which changes with time)

(1/2)q x q = C x Joule (Energy)

Then,

Joule (Energy) = (1/2)q x q x 1/C, which is again

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We want to add one more explanation in a similar but more general way so that it easily leads to a analogous explanation of Energy stored in an inductor

Basic function of a capacitor is as above used

i(t)= \frac{\mathrm{d}q(t)}{\mathrm{d}t}=C\frac{\mathrm{d}v(t)}{\mathrm{d}t}

Integrate the both sides with respect to time

(q/time) x time = C v

q = Cv =C x Joule (Energy)/q

The unit of q is Ampere x second.

Integrate the both sides with respect to voltage (0 to final V).

Ampere x second x voltage = formula002


Ampere x second x voltage or IV (Power) x time = Energy, So

Energy = formula002



2) Energy stored in an inductor


Basic function related with
Inductance, Current (changing) and Voltage (changing) of an inductor is

v(t) = L \frac{di(t)}{dt}
Integrate the both sides with respect to time

voltage x time = Li

(note Unit
Weber is voltage x time (in second) or L(Weber/Ampere) x i (Ampere)

Integrate the both sides with respect to Current (0 to final Current).


Voltage x time x Current = ½LI²


Voltage x Time (second) x Current or VI (Power) x time = Energy, So


Energy = ½LI²


---- End----


sptt

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